Log in! (forgot password)
Username: Password:
Back The Easy Sum... Random ??? Next The Middle o...
All Puzzles / Logical /

The Classic Weights & Scale

You have 8 lead marbles, one of which is heavier than the rest. What is the minimum amount of “weightings” (i.e. with a see-saw scale) you need to do to guarantee finding the odd one out?

Ist2_366762-balanced-brass-scale
Bookmark and Share
(Show)
(Show)
People who liked this also liked: Manholes | Three Idols | Guess the Phrase |

Discussion

comments with spoilers hidden | Show All
folcklord about 1 month ago
phentermine online ybtjgw Accutane online :-] doxycycline 454601 accutane online itrrqa
folcklord about 1 month ago
xanax 336 Tramadol online 4581 buy xanax %-]] buy tramadol 67103 carisoprodol domain soma vkxfdz
bobmarks about 1 month ago

just coming by form angular cheilitis site for a treatment its at angular cheilitis home treatment if anyone else has angular cheilitis

greatgray 7 months ago

I thought that the answer was 3.(log-2 of 8)

kzer95 8 months ago

@sysop073:
the scale is not binary, the scale has 3 states, less heavy, more heavy and equal

therefore the answer is ceil ( log_base3( number of marbles) ). i think

walkingagh about 1 year ago

could also do this with 9 balls and have the same answer

kash about 1 year ago contains spoiler (show)
sleepib about 1 year ago contains spoiler (show)
bughill about 1 year ago

Here is another puzzle, much harder but can be done. Given 11 billiard balls all of which weigh the same and a 12th that is either lighter or heavier than the others, determine in a max of 3 uses of the scale which is the odd ball and if it is lighter or heavier than the others. Same type of scale.

Google:
“12 billiard balls” weigh
for numerous solutions

sysop073 about 1 year ago contains spoiler (show)